1.如果有一个自动增长的id字段,则:
定义二个变量:Page,PageCount
Select top PageCount * From [tb_code] Where id>=(select min(id) from (select top (Page-1)*PageCount+1 id from [tb_code] order by id desc) as t) order by id desc
原理,根据ID计算出(Page-1)页的最小值,然后用TOP关键字及可解决问题。
2.SELECT TOP 10 id,username From [tb_code] where id not in
( SELECT TOP 20000 id FROM tb_code ORDER BY username)
优点:此方法可以根据表中的任一个字段排序,在一个表中有几百万条记录时,仍有很高的效率,缺点是在大数据量的情况下效率略逊于第一种
3.SELECT TOP 10 id,username From
(SELECT TOP page*pagecount id, username FROM tb_code ORDER BY username)
DERIVEDTBL ORDER BY username DESC
优点:此方法可以根据表中的任一个字段排序.
缺点是效率最低
使用row_number分页
declare @startRowIndex int;
declare @endRowIndex int;
declare @maximumRows int;
set @startRowIndex=2;
set @endRowIndex=2;
set @maximumRows=2;
SELECT * from (SELECT id,row_number() over(order by id) as rownum
FROM [tb].[dbo].[b] ) as t
where t.rownum>@startRowIndex and t.rownum<=@endRowIndex+@maximumRows