需求
oracle某字段存放的是逗号分隔的id字符串。 现在需要通过id来筛选,且id可以多选 与逻辑。
比如:id字符串为1,2,3,4,5 搜索条件为1,3
思路
mysql 有 find_in_set函数可以满足类似需求,oracle没有这个函数,需要手动创建
create or replace function find_in_set(arg1 in varchar2,arg2 in varchar)
return number is Result number;
begin
select instr(','||arg2||',' , ','||arg1||',') into Result from dual;
return(Result);
end find_in_set;
find_in_set 传入参数是一个元素 。该需求下传入元素是多个,则输入参数拆分成list,循环调用find_in_set
代码
controller
if (tags != null){
where.put("tags", Arrays.asList(tags.split(",")));
}
return iOrderInfoService.getOrder(where);
xml
<if test="tags != null and tags.size() > 0">
<foreach collection="tags" item="item" index="index">
and FIND_IN_SET( #{item} , TAGS) > 0
</foreach>
</if>
<if test="tags != null and tags.size() == 0">
and 1 = 0
</if>
参考文章: https://blog.youkuaiyun.com/iteye_7222/article/details/82552663,
https://blog.youkuaiyun.com/iteye_7222/article/details/82552663