快速幂取模

Given a b and p, output (a^b) % p   (2<=a<=100, 0<=b<=1000000000,  3<=p<=10000)

 

 

1. #include<stdio.h>
2. #include<stdlib.h>
3. #include<string.h>
4.  
5. int quick_power(int a,int b,int p){
6. int temp;
7. if(b ==0){
8. return1;
9. }
10. temp = quick_power(a, b /2, p);
11. if(b &1){
12. return(((temp * temp)% p)*(a % p))% p;
13. }else{
14. return(temp * temp)% p;
15. }
16. }
17.  
18. int main(int argc,char*argv[]){
19. int a, b, p;
20.  
21. while(~scanf("%d%d%d",&a,&b,&p)){
22. printf("%d\n", quick_power(a, b, p));
23. }
24. return0;
25. }

转载于:https://www.cnblogs.com/sysu-zhengwsh/p/3674196.html