1001 A+B Format-PAT甲级

原创于 2019-08-20 13:27:12 发布 · 76 阅读

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本文介绍了一个使用C++实现的简单程序，该程序接收两个整数输入，计算它们的和，并以标准格式输出结果，即每三位数字用逗号分隔。示例输入为-1000000和9，输出结果为-999,991。此程序展示了如何使用字符串流进行数字到字符串的转换，以及如何正确地格式化输出。

Calculate a+b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input Specification:

Each input file contains one test case. Each case contains a pair of integers a and b where −106≤a,b≤106. The numbers are separated by a space.

Output Specification:

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input:

-1000000 9

Sample Output:

-999,991

后面每三位为一组，前面为一个逗号

#include<bits/stdc++.h>
using namespace std;
int main(){
	int a,b,c;
	scanf("%d%d",&a,&b);
	c=a+b;
	string s;
	stringstream ss;
	ss<<c;
	ss>>s;
	if(s[0]=='-'){
		cout<<"-";
		s=s.substr(1);
	}
	int k=s.size()%3;
	if(k!=0){
		for(int i=0;i<k;i++)
			cout<<s[i];
	}
	for(int i=k;i<s.size();i++){
		if((i-k)%3==0&&i>0)
			cout<<",";
		cout<<s[i];
	}
	return 0;
}