<?xml version="1.0" encoding="utf-8" ?><rss version="2.0"><channel><title><![CDATA[amber_o0k的博客]]></title><description><![CDATA[]]></description><link>https://blog.youkuaiyun.com/amber_o0k</link><language>zh-cn</language><generator>https://blog.youkuaiyun.com/</generator><copyright><![CDATA[Copyright &copy; amber_o0k]]></copyright><item><title><![CDATA[2026 能源网络安全大赛 crypto 2]]></title><link>https://blog.youkuaiyun.com/amber_o0k/article/details/162791984</link><guid>https://blog.youkuaiyun.com/amber_o0k/article/details/162791984</guid><author>amber_o0k</author><pubDate>Sat, 11 Jul 2026 14:56:52 +0800</pubDate><description><![CDATA[附件给出了曲线名称、公开密钥、未知低位长度，以及多条签名记录和对应的随机数高位窗口。请利用这些不完整的窗口信息恢复签名私钥。私钥按大端字节还原后就是本题 flag。某个安全芯片在调试模式下会输出 ECDSA 签名过程中的一小段运行窗口。开发人员只保留了每次随机数的高位部分，认为低位没有公开，因此不会泄露私钥。]]></description><category></category></item><item><title><![CDATA[2026 能源网络安全大赛 crypto 1]]></title><link>https://blog.youkuaiyun.com/amber_o0k/article/details/138814364</link><guid>https://blog.youkuaiyun.com/amber_o0k/article/details/138814364</guid><author>amber_o0k</author><pubDate>Sat, 11 Jul 2026 14:54:59 +0800</pubDate><description><![CDATA[【代码】2026 能源网络安全大赛 crypto 1。]]></description><category></category></item><item><title><![CDATA[pwn-fmt泄露pie_base,有后门函数]]></title><link>https://blog.youkuaiyun.com/amber_o0k/article/details/149524548</link><guid>https://blog.youkuaiyun.com/amber_o0k/article/details/149524548</guid><author>amber_o0k</author><pubDate>Tue, 22 Jul 2025 07:26:13 +0800</pubDate><description><![CDATA[【代码】pwn-fmt泄露pie_base,有后门函数。]]></description><category></category></item><item><title><![CDATA[sha系列对比]]></title><link>https://blog.youkuaiyun.com/amber_o0k/article/details/148313466</link><guid>https://blog.youkuaiyun.com/amber_o0k/article/details/148313466</guid><author>amber_o0k</author><pubDate>Thu, 29 May 2025 16:45:43 +0800</pubDate><description><![CDATA[]]></description><category></category></item><item><title><![CDATA[python精度问题，两个数不等但相减为零]]></title><link>https://blog.youkuaiyun.com/amber_o0k/article/details/147620091</link><guid>https://blog.youkuaiyun.com/amber_o0k/article/details/147620091</guid><author>amber_o0k</author><pubDate>Tue, 29 Apr 2025 21:32:47 +0800</pubDate><description><![CDATA[（整数）在 Python 中可以无限大（仅受内存限制），存储的是。进行减法计算时，x_acc会被转为float。（64位），只能精确表示大约。]]></description><category></category></item><item><title><![CDATA[2025能源网络安全大赛CTF，crypto，电网组]]></title><link>https://blog.youkuaiyun.com/amber_o0k/article/details/147357259</link><guid>https://blog.youkuaiyun.com/amber_o0k/article/details/147357259</guid><author>amber_o0k</author><pubDate>Sat, 19 Apr 2025 22:57:40 +0800</pubDate><description><![CDATA[【代码】2025能源网络安全大赛CTF-cy，电网组。]]></description><category></category></item><item><title><![CDATA[【rsa】dp leak]]></title><link>https://blog.youkuaiyun.com/amber_o0k/article/details/146810614</link><guid>https://blog.youkuaiyun.com/amber_o0k/article/details/146810614</guid><author>amber_o0k</author><pubDate>Mon, 31 Mar 2025 12:01:25 +0800</pubDate><description><![CDATA[无需爆破em%n同余m%pm%n同余m%q。]]></description><category></category></item><item><title><![CDATA[[nsscft]littleprince]]></title><link>https://blog.youkuaiyun.com/amber_o0k/article/details/146512620</link><guid>https://blog.youkuaiyun.com/amber_o0k/article/details/146512620</guid><author>amber_o0k</author><pubDate>Tue, 25 Mar 2025 21:02:00 +0800</pubDate><description><![CDATA[outp是四字节x对p,q取模的结果，使用crt定理可破，但需注意的是x可能大于p*q,而crt求得的解是p*q范围内的最小整数解，所以需要时手动找一下。enc是四字节循环右移。]]></description><category></category></item><item><title><![CDATA[nist关于rsa中p,q的要求]]></title><link>https://blog.youkuaiyun.com/amber_o0k/article/details/145955119</link><guid>https://blog.youkuaiyun.com/amber_o0k/article/details/145955119</guid><author>amber_o0k</author><pubDate>Sat, 01 Mar 2025 22:42:05 +0800</pubDate><description><![CDATA[1)，也规定了d的范围，一般来说d是接近的n的，很难被爆破。这些数都应含有大的素因子以对抗光滑数分解。.p和q具有足够的距离以对抗费马分解。–1)，并非常见的n的欧拉函数。3，计算逆元的模用的LCM(]]></description><category></category></item><item><title><![CDATA[破解rsa的思路]]></title><link>https://blog.youkuaiyun.com/amber_o0k/article/details/145480389</link><guid>https://blog.youkuaiyun.com/amber_o0k/article/details/145480389</guid><author>amber_o0k</author><pubDate>Thu, 06 Feb 2025 19:09:13 +0800</pubDate><description><![CDATA[分解n（试除法，费马分解，pollard p-1，光滑数相关，椭圆曲线，数域筛nfs）知道p，q的某种线性关系，分解n。]]></description><category></category></item><item><title><![CDATA[https数字签名手动验签]]></title><link>https://blog.youkuaiyun.com/amber_o0k/article/details/145383055</link><guid>https://blog.youkuaiyun.com/amber_o0k/article/details/145383055</guid><author>amber_o0k</author><pubDate>Mon, 27 Jan 2025 22:50:08 +0800</pubDate><description><![CDATA[以bing.com 为例。]]></description><category></category></item><item><title><![CDATA[2024网鼎杯，朱雀，crypto1，题干]]></title><link>https://blog.youkuaiyun.com/amber_o0k/article/details/143503093</link><guid>https://blog.youkuaiyun.com/amber_o0k/article/details/143503093</guid><author>amber_o0k</author><pubDate>Tue, 05 Nov 2024 10:53:24 +0800</pubDate><description><![CDATA[关于格密码， 貌似当时零解。]]></description><category></category></item><item><title><![CDATA[2024网鼎杯，朱雀，crypto2]]></title><link>https://blog.youkuaiyun.com/amber_o0k/article/details/143502973</link><guid>https://blog.youkuaiyun.com/amber_o0k/article/details/143502973</guid><author>amber_o0k</author><pubDate>Tue, 05 Nov 2024 10:48:28 +0800</pubDate><description><![CDATA[【代码】2024网鼎杯，朱雀，crypto2。]]></description><category></category></item><item><title><![CDATA[2024网鼎杯，朱雀，crypto3]]></title><link>https://blog.youkuaiyun.com/amber_o0k/article/details/143486552</link><guid>https://blog.youkuaiyun.com/amber_o0k/article/details/143486552</guid><author>amber_o0k</author><pubDate>Mon, 04 Nov 2024 15:50:47 +0800</pubDate><description><![CDATA[【代码】2024网鼎杯，朱雀，crypto3。]]></description><category></category></item><item><title><![CDATA[sage,ecc,已知kp，k求p]]></title><link>https://blog.youkuaiyun.com/amber_o0k/article/details/143442912</link><guid>https://blog.youkuaiyun.com/amber_o0k/article/details/143442912</guid><author>amber_o0k</author><pubDate>Fri, 01 Nov 2024 23:24:32 +0800</pubDate><description><![CDATA[还是gpt老师厉害，虽然前两次回答都不靠谱。]]></description><category></category></item><item><title><![CDATA[[dasctf]howtodecompile]]></title><link>https://blog.youkuaiyun.com/amber_o0k/article/details/143262887</link><guid>https://blog.youkuaiyun.com/amber_o0k/article/details/143262887</guid><author>amber_o0k</author><pubDate>Sun, 27 Oct 2024 02:00:55 +0800</pubDate><description><![CDATA[为真正flag部分。操作流程类似上面那样nop相关代码。最里面的类似,但没找到要点，非准确结果如下。dword_41DC30有用。看汇编，这里有问题造成ida无法识别函数边界，将对应的机器码改为90.回到函数起始部分，按P重建函数即可显示反汇编代码。上来就是个jumpout。]]></description><category></category></item><item><title><![CDATA[[reverse]河北省职工职业技能大赛决赛re2(rotate-xtea-aes)]]></title><link>https://blog.youkuaiyun.com/amber_o0k/article/details/141596257</link><guid>https://blog.youkuaiyun.com/amber_o0k/article/details/141596257</guid><author>amber_o0k</author><pubDate>Tue, 27 Aug 2024 10:37:57 +0800</pubDate><description><![CDATA[aes如果ida有findcrypt插件能直接识别， 或者看到sbox，63,7c打头也能想到了。脚本内的xtea的key并未用到。可根据算法手动计算xtea内部异或用到的数（4字节无符号数）。注意最后密文显示是小端序模式，在脚本解密时，应按8字节逆转。xtea部分同理，按4字节逆转。流程是输入的字符每两个转为一个字节，单字节循环左移，xtea加密，aes加密。还好只有一个分组，且并没用少见的加密模式。xtea做的不多第一眼看过去确实有点蒙。]]></description><category></category></item><item><title><![CDATA[[lcg]a,b,m未知，求初始seed。Homoo00。]]></title><link>https://blog.youkuaiyun.com/amber_o0k/article/details/141039858</link><guid>https://blog.youkuaiyun.com/amber_o0k/article/details/141039858</guid><author>amber_o0k</author><pubDate>Fri, 09 Aug 2024 01:15:05 +0800</pubDate><description><![CDATA[【代码】[lcg]a,b,m未知，求初始seed。]]></description><category></category></item><item><title><![CDATA[素数的一个性质]]></title><link>https://blog.youkuaiyun.com/amber_o0k/article/details/140621614</link><guid>https://blog.youkuaiyun.com/amber_o0k/article/details/140621614</guid><author>amber_o0k</author><pubDate>Mon, 22 Jul 2024 22:57:11 +0800</pubDate><description><![CDATA[2,a^q,a^2q,a^((2^2)q)... ... a^((2^(k-1))q)之一摸p余-1。设p是奇素数，记p-1=(2^k)*q,q是奇数。]]></description><category></category></item><item><title><![CDATA[【moyu】河北省职工职业技能大赛决赛]]></title><link>https://blog.youkuaiyun.com/amber_o0k/article/details/140589824</link><guid>https://blog.youkuaiyun.com/amber_o0k/article/details/140589824</guid><author>amber_o0k</author><pubDate>Sun, 21 Jul 2024 16:24:18 +0800</pubDate><description><![CDATA[【代码】【moyu】河北省职工职业技能大赛决赛。]]></description><category></category></item></channel></rss>