\sum\limits_{i=1}^n i^2 = \frac{n(n+1)(2n+1)}{6}
加和公式为∑i=1ni2=n(n+1)(2n+1)6\sum\limits_{i=1}^n i^2 = \frac{n(n+1)(2n+1)}{6}i=1∑ni2=6n(n+1)(2n+1)
\sum\nolimits_{P_i \in Paths(I)} Probes(P_{i})
加和公式为 ∑Pi∈Paths(I)Probes(Pi)\sum\nolimits_{P_i \in Paths(I)} Probes(P_{i})∑Pi∈Paths(I)Probes(Pi)