Given a string, find the length of the longest substring without repeating characters.
Example 1:
Input: "abcabcbb"
Output: 3
Explanation: The answer is "abc", with the length of 3.
Example 2:
Input: "bbbbb"
Output: 1
Explanation: The answer is "b", with the length of 1.
Example 3:
Input: "pwwkew"
Output: 3
Explanation: The answer is "wke", with the length of 3.
Note that the answer must be a substring, "pwke" is a subsequence and not a substring.
MyAnswer
class Solution {
public int lengthOfLongestSubstring(String s) {
int i=0,j=0,max=0;
Set<Character> set = new HashSet<>();
while (j<s.length()){
if (!set.contains(s.charAt(j))){
set.add(s.charAt(j++));
max = Math.max(max,set.size());
}else {
set.remove(s.charAt(i++));
}
}
return max;
}
}
本文详细解析了寻找字符串中最长无重复字符子串的算法实现,通过具体示例展示了如何利用HashSet数据结构和双指针技术高效解决此问题。文章提供了完整的Java代码示例,深入探讨了算法的时间复杂度和空间复杂度。
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