FZU 1733 Image Distortion

本文介绍了一种简单的方法来计算二值图像在传输过程中产生的位错误总数。通过对比传输前后图像的每个像素位,可以快速统计出位错误的数量。

摘要生成于 C知道 ,由 DeepSeek-R1 满血版支持, 前往体验 >

 

Image Distortion
Time Limit:1sMemory limit:32M
Accepted Submit:77Total Submit:100

 

In the process of transmission, data loss may occur, resulting in image distortion and so on. To simplify the problem, we consider an image whose pixel is a single bit (0 or 1), and then the bit errors could be: 1 to 0 or 0 to 1.
You should calculate the total bit errors in the process of transmission.

Input

 

There are multiple test cases. For each test case, the first line contains two integers N and M (2≤N,M≤100), indicating the size of the image. The next N lines, each line contains M characters, these N*M characters indicate the image before transmission. The next N lines, each line contains M characters, these N*M characters indicate the image after transmission. The character is either 0 or 1.

 

Output

 

For each test case, output an integer indicating the total bit errors in the process of transmission.

 

Sample Input

7 7
0000000
0111110
0101010
0111110
0101010
0111110
0000000
0000000
0110110
0111010
0110110
0101010
0111110
0000000

Sample output

3

Original: FZU 2009 Summer Training Qualification -- Hero Revival 3

 

解题:

        水题,刷数量.....

评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值