进制转换,10进制转换成16进制。循环求余,余的逆序就是我们要的结果,当然不能直接输出,还必须输出对应的字符(10-->A, 11-->B等)。
#include <iostream>
#include <fstream>
#include <vector>
using namespace std;
const int MAX_SIZE = 32 + 2;
char BASE[] = {'0', '1', '2', '3', '4', '5','6','7',
'8', '9', 'A', 'B', 'C', 'D', 'E', 'F'};
//#define yangyuan
int main()
{
#ifdef yangyuan
ifstream in("in.txt");
cin.rdbuf(in.rdbuf());
#endif // yangyuan
vector<int> data;
data.reserve(MAX_SIZE);
int n, base;
while (cin >> n >> base)
{
bool positive = true;
if (n < 0)
{
positive = false;
n = -n;
}
do
{
data.push_back(n % base);
} while (n /= base);
if (! positive)
cout << "-";
for (int i = data.size() - 1; i >= 0; i--)
{
cout << BASE[data[i]];
}
cout << endl;
data.resize(0);
}
return 0;
}