1108 Finding Average (20 分)
The basic task is simple: given N real numbers, you are supposed to calculate their average. But what makes it complicated is that some of the input numbers might not be legal. A legal input is a real number in [−1000,1000] and is accurate up to no more than 2 decimal places. When you calculate the average, those illegal numbers must not be counted in.
Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (≤100). Then N numbers are given in the next line, separated by one space.
Output Specification:
For each illegal input number, print in a line ERROR: X is not a legal number where X is the input. Then finally print in a line the result: The average of K numbers is Y where K is the number of legal inputs and Y is their average, accurate to 2 decimal places. In case the average cannot be calculated, output Undefined instead of Y. In case K is only 1, output The average of 1 number is Y instead.
Sample Input 1:
7
5 -3.2 aaa 9999 2.3.4 7.123 2.35
Sample Output 1:
ERROR: aaa is not a legal number
ERROR: 9999 is not a legal number
ERROR: 2.3.4 is not a legal number
ERROR: 7.123 is not a legal number
The average of 3 numbers is 1.38
Sample Input 2:
2
aaa -9999
Sample Output 2:
ERROR: aaa is not a legal number
ERROR: -9999 is not a legal number
The average of 0 numbers is Undefined
#include<iostream>
#include<vector>
#include<map>
#include<string>
#include<cstring>
#include<cstdio>
#include<cctype>
using namespace std;
int main(){
int n;
cin >> n;
string s[101];
vector<string> v;
for(int i = 0;i < n;i++){
cin >> s[i];
}
int flag,dem;
for(int i = 0;i < n;i++){
flag = 0;
dem = 0;
for(int j = 0;j < s[i].length();j++){
if(j==0&&s[i][j]=='-'){
j++;
}
if(s[i][j]=='.'){
dem++;
//cout << s[i].length() << " " << j;
if(j==0 || dem>1 || s[i].length() - j > 3){
flag = 1;
printf("ERROR: %s is not a legal number\n",s[i].c_str());
break;
}
}else if(isdigit(s[i][j])){
}else{
flag = 1;
printf("ERROR: %s is not a legal number\n",s[i].c_str());
break;
}
}
if(flag==0){
if(stof(s[i]) < -1000 || stof(s[i]) > 1000){
printf("ERROR: %s is not a legal number\n",s[i].c_str());
}
else
v.push_back(s[i]);
}
}
if(v.size()==0){
printf("The average of 0 numbers is Undefined\n");
}else if(v.size() == 1){
printf("The average of %d number is %.2f\n",v.size(),stof(v[0]));
}else{
double sum = 0;
for(int i = 0;i < v.size();i++){
sum+=stof(v[i]);
}
printf("The average of %d numbers is %.2f\n",v.size(),sum/v.size());
}
return 0;
}
本文介绍了一种算法,用于从一组输入中筛选出合法的数值(位于-1000到1000之间且最多两位小数),并计算这些合法数值的平均值。文章详细解释了如何判断数值的合法性,以及如何排除非法数值进行平均值计算。
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