Guess the number
Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 4142 Accepted Submission(s): 3077
Problem Description
Happy new year to everybody!
Now, I want you to guess a minimum number x betwwn 1000 and 9999 to let
(1) x % a = 0;
(2) (x+1) % b = 0;
(3) (x+2) % c = 0;
and a, b, c are integers between 1 and 100.
Given a,b,c, tell me what is the number of x ?
Input
The number of test cases c is in the first line of input, then c test cases followed.every test contains three integers a, b, c.
Output
For each test case your program should output one line with the minimal number x, you should remember that x is between 1000 and 9999. If there is no answer for x, output “Impossible”.
Sample Input
2
44 38 49
25 56 3
Sample Output
Impossible
2575
#include <stdio.h>
#include <stdlib.h>
int main()
{
int t,a,b,c,i;
while(scanf("%d",&t)!=EOF)
{
if(t==0)break;
while(t--)
{
int m=0;
scanf("%d%d%d",&a,&b,&c);
for(i=1000;i<9999;i++)
{
if(i%a==0&&(i+1)%b==0&&(i+2)%c==0)
{
m=i;
break;
}
}
if(m==0)
{
printf("Impossible\n");
}
else
{
printf("%d\n",m);
}
}
}
return 0;
}