| Time Limit: 1000MS | Memory Limit: Unknown | 64bit IO Format: %lld & %llu |
Description
Problem G
Triangle Counting
Input: Standard Input
Output: Standard Output

You are given n rods of length 1, 2…, n. You have to pick any 3 of them & build a triangle. How many distinct triangles can you make? Note that, two triangles will be considered different if they have at least 1 pair of arms with different length.
Input
The input for each case will have only a single positive integer n (3<=n<=1000000). The end of input will be indicated by a case with n<3. This case should not be processed.
Output
For each test case, print the number of distinct triangles you can make.
Sample Input Output for Sample Input
| 5 8 0 | 3 22 |
Problemsetter: Mohammad Mahmudur Rahman
分析:
刘汝佳大白书里的数学水题。
ac代码:
#include <iostream>
#include<cstdio>
using namespace std;
const int maxn=1000000+10;
long long f[maxn];
int main()
{
f[3]=0;
for(long long x=4;x<=maxn;x++)//x用long long,因为中间计算int会溢出
f[x]=f[x-1]+((x-1)*(x-2)/2-(x-1)/2)/2;
int n;
while(scanf("%d",&n)!=EOF)
{
if(n<3) break;
printf("%lld\n",f[n]);
}
return 0;
}
探讨了给定一系列不同长度的杆子如何构建不同的三角形的问题,并提供了一个有效的算法实现。
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