杭电1228 a+b

Problem Description

读入两个小于100的正整数A和B,计算A+B.
需要注意的是:A和B的每一位数字由对应的英文单词给出.

Input

测试输入包含若干测试用例,每个测试用例占一行,格式为"A + B =",相邻两字符串有一个空格间隔.当A和B同时为0时输入结束,相应的结果不要输出. 

Output

对每个测试用例输出1行,即A+B的值.

Sample Input

one + two =

three four + five six =

zero seven + eight nine =

zero + zero =

Sample Output

3

90

96

Source

浙大计算机研究生复试上机考试-2005年

#include <iostream>
#include <stdio.h>
#include<string.h>
char num[10][6]= {"zero","one","two","three","four","five","six","seven","eight","nine"};
using namespace std;
int ex(char s[])//进行比较 判断出输入的数字的大小
{
    for(int i=0; i<10; i++)
    {
        if(strcmp(s,num[i])==0)
        return i;
    }
}
int main()
 {
    char s[10];
    while(true)
    {
        int ta=0,tb=0;
        while(scanf("%s",s),strcmp(s,"+")!=0)//%s不接受空格
        {
                ta=ta*10+ex(s);//调用ex
        }
        while(scanf("%s",s),strcmp(s,"=")!=0)
        {
            tb=tb*10+ex(s);
        }
        if(ta==0&&tb==0)//当输入的均为0时 结束
            break;
        else
            printf("%d\n",ta+tb);
    }
    return 0;
}