PTA乙级训练题1001-1012解答（C语言）

1001【答案】

#include <stdio.h>
int main(){
    int n;int i=0;
    scanf("%d",&n);
    while(n!=1){
    if(n%2==0)
        n/=2;
    else 
        n=(n*3+1)/2;
        i++;
    }
    printf("%d",i);
}

1002【答案】

#include <stdio.h>
void print(int a){
  switch (a){
   case 0:
        printf ("ling");
        break;
   case 1:
        printf ("yi");
        break;
   case 2:
        printf ("er");
        break;
   case 3:
        printf ("san");
        break;
   case 4:
        printf ("si");
        break;
   case 5:
        printf ("wu");
        break;
   case 6:
        printf ("liu");
        break;
   case 7:
        printf ("qi");
        break;
   case 8:
        printf ("ba");
        break;
   case 9:
        printf ("jiu");
        break;
   default:
        break;

  }
}
int main(){
 char num[105];
 int sum=0;int i = 0;
 int hund = 0,dec = 0,unit = 0;//百、十、个
 scanf("%s",num);
  for(;num[i]!='\0';i++){
    sum += (num[i]-'0'); 
  }
  //printf("%d",sum);
  if(sum>=100){
        unit = sum % 10;
        //printf("%d ",unit);
        dec = (sum/10)%10;
        //printf("%d ",dec);
        hund = sum/100;
        //printf("%d ",hund);
        print(hund);
        printf(" ");
        print(dec);
        printf(" ");
        print(unit);

  } else if(sum >= 10){
    unit = sum%10;
        dec = sum / 10;
        print(dec);
        printf(" ");
        print(unit);
  }else {
    unit = sum;
        print(unit);
  }
  return 0;
}

1003【答案】

#include <stdio.h>
int Judge(char ch[]){
  int i=0;int tag = 1;int T_time=0,P_time=0;
  int A_time_front=0,A_time_last=0;
  int A_time_mid =0;
  int A_time=0;

  while(ch[i]!='\0'){
    if(ch[i]!='A'&&ch[i]!='P'&&ch[i]!='T'){
      tag=0;
      break;
    }//字符串中必须仅有P,A,T三种字符 
    else if(ch[i]==