题意:求a到b区间中,能开尽平方的数,比如,1,4,9,16
思路:智障题目。统计转化为区间。
代码:
#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <cmath>
#include <queue>
#include <vector>
#define DB puts("**de**")
#define WATCH(a) cout << a << endl
#define REP(i,n) for(int i=0;i<n;++i)
#define FF(i,a,b) for(int i=a;i<=b;++i)
#define CL(a,b) memset(a,b,sizeof(a))
#define LL long long
#define FD(i,a,b) for(int i=a;i>=b;--i)
#define pb push_back
#define pr pair<int,int >
//#pragma comment(linker, "/STACK:1024000000,1024000000")
using namespace std;
//const
const int MAXN=1e6+5;
const int INF=0x3f3f3f3f;
//struct
//global
//vector<int> edge[MAXN];
int ti1,ti2,ti3,n,m,t,ncase;
bool vis[1000005];
int num[1000005];
double td1,td2,td3;
char tc1,tc2;
//func
int main()
{
//freopen("C:\\Users\\inkysakura\\Desktop\\testdata.txt","r",stdin);
for(int i=1;i<=1000;i++)vis[i*i]=1;
for(int i=1;i<=1000000;i++)
if(vis[i])num[i]=num[i-1]+1;else num[i]=num[i-1];
while(scanf("%d %d",&n,&m),n&&m)
{
cout << num[m]-num[n-1]<<endl ;
}
return 0;
}