复数运算-优快云博客

本文介绍了一个简单的C++程序，用于实现复数的加、减、乘、除运算。通过定义复数类并重载算术运算符，实现了复数之间的基本运算。

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#include<iostream>  
using namespace std;
class Complex  
{  
public:  
    Complex(){real=0;imag=0;}  
    Complex(double r,double i){real=r;imag=i;}  
    Complex operator+(Complex &c2);  
    Complex operator-(Complex &c2);  
    Complex operator*(Complex &c2);  
    Complex operator/(Complex &c2);  
	friend ostream& operator << (ostream&,Complex&);
	friend istream& operator >> (istream&,Complex&);
private:  
    double real;  
    double imag;  
};  
//下面定义成员函数  
istream& operator >> (istream& input,Complex& c)
{ 
	input>>c.real>>c.imag;
	return input;
}
ostream& operator << (ostream& output,Complex& c)
{
	output<<"("<<c.real<<" "<<c.imag<<"i)"<<endl;
	return output;
}
//复数相加： (a+bi)+(c+di)=(a+c)+(b+d)i.  
Complex Complex::operator+(Complex &c2)      
{    
    Complex c;     
    c.real=real+c2.real;    
    c.imag=imag+c2.imag;    
    return c;    
}    


//复数相减：(a+bi)-(c+di)=(a-c)+(b-d)i.        
Complex Complex::operator-(Complex &c2)        
{        
    Complex c;        
    c.real=real-c2.real;        
    c.imag=imag-c2.imag;        
    return c;        
}        

//复数相乘：(a+bi)(c+di)=(ac－bd)+(bc+ad)i.    

Complex Complex::operator*(Complex &c2)   
{        
    Complex  c;        
    c.real=real*c2.real-imag*c2.imag;        
    c.imag=imag*c2.real+real*c2.imag;        
    return c;        
}        

//复数相除：(a+bi)/(c+di)=(ac+bd)/(c^2+d^2) +(bc-ad)/(c^2+d^2)i    
Complex Complex::operator/(Complex &c2)   
{        
    Complex  c;        
    double d=c2.real*c2.real+c2.imag*c2.imag;    
    c.real=(real*c2.real+imag*c2.imag)/d;     //此处有危险未排除：除法溢出    
    c.imag=(imag*c2.real-real*c2.imag)/d;        
    return c;        
}     

int main()  
{  
    Complex c1,c2,c3; 
	cout<<"请输入复数c1的值：（以a b的形式输入）";
	cin>>c1;
	cout<<"请输入复数c2的值：（以a b的形式输入）";
	cin>>c2;
    cout<<"c1=";  
    cout<<c1;  
    cout<<"c2=";  
    cout<<c2;  
    c3=c1+c2;  
    cout<<"c1+c2=";  
    cout<<c3;  
    c3=c1-c2;  
    cout<<"c1-c2=";  
    cout<<c3;  
    c3=c1*c2;  
    cout<<"c1*c2=";  
    cout<<c3;  
    c3=c1/c2;  
    cout<<"c1/c2=";  
    cout<<c3; 
    system("pause");
    return 0;  
}

第九周任务1