Given a pattern and a string str,
find if str follows the same pattern.
Here follow means a full match, such that there is a bijection between a letter in pattern and
a non-empty word in str.
Examples:
- pattern =
"abba", str ="dog cat cat dog"should return true. - pattern =
"abba", str ="dog cat cat fish"should return false. - pattern =
"aaaa", str ="dog cat cat dog"should return false. - pattern =
"abba", str ="dog dog dog dog"should return false.
Notes:
You may assume pattern contains only lowercase letters, and str contains
lowercase letters separated by a single space.
Java:
public class Solution {
public boolean wordPattern(String pattern, String str) {
String[] array = str.split(" ");
HashMap<Character,String> hashmap = new HashMap<Character, String>();
if(array.length != pattern.length()) return false;
for(int i=0; i<pattern.length(); i++)
{
String s = hashmap.get(pattern.charAt(i));
if(s!= null && !s.equals(array[i]) )
{
return false;
}else if(s==null && hashmap.containsValue(array[i]))
{
return false;
}else if(s == null)
{
hashmap.put(pattern.charAt(i),array[i]);
}
}
return true;
}
}
本文介绍了一种模式匹配算法,该算法用于判断给定的字符串是否遵循特定的模式。通过使用哈希映射实现,确保模式中的每个字符与字符串中非空单词的一一对应关系。
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