#include<stdio.h>
#include<stdlib.h>
int leap_year(int year)
{
return (((year%4==0) && (year%100!=0)) ||( year%400 ==0));
}
int main()
{
int re = 0;
int year = 0;
printf("请输入年份:");
scanf("%d",&year);
re = leap_year(year);
if(re)
{
printf("是润年");
}
else
{
printf("不是润年");
}
system("pause");
return 0;
}
函数判断year是不是润年
最新推荐文章于 2022-04-07 10:54:35 发布