带权并查集
sum[i]记录i这列有多少个战舰。num[i]记录i前面有多少个战舰。找爸爸的时候更新即可。
代码:
#include<cstdio>
#include<algorithm>
#include<cstring>
#define MAXN 30000
using namespace std;
int fa[MAXN+5],num[MAXN+5],sum[MAXN+5];
int n;
char readc(){
static char buf[100000],*l=buf,*r=buf;
if (l==r) r=(l=buf)+fread(buf,1,100000,stdin);
if (l==r) return EOF;
else return *l++;
}
inline int _read(){
int num=0; char ch=readc();
while ((ch<'0'||ch>'9')&&ch!='M'&&ch!='C') ch=readc();
if (ch=='M'||ch=='C') return (int)ch;
while (ch>='0'&&ch<='9'){ num=num*10+ch-48; ch=readc(); }
return num;
}
int findfather(int x){
if (fa[x]==x)
return x;
int fat=fa[x];
fa[x]=findfather(fa[x]);
num[x]+=num[fat];
return fa[x];
}
int main(){
n=_read();
for (int i=1;i<=MAXN;i++){
fa[i]=i;
sum[i]=1;
}
while (n--){
int flag=_read(),x=_read(),y=_read();
if (flag=='M'){
int fx=findfather(x),fy=findfather(y);
fa[fx]=fy;
num[fx]+=sum[fy];
sum[fy]+=sum[fx];
}
if (flag=='C'){
int fx=findfather(x),fy=findfather(y);
if (fx!=fy)
printf("-1\n");
else
printf("%d\n",abs(num[y]-num[x])-1);
}
}
return 0;
}