CodeForces - 811A

本文详细解析了CodeForces竞赛中的811A题目,适合初学者理解,涵盖解题思路、算法实现及常见错误分析,帮助提升编程竞赛能力。

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At regular competition Vladik and Valera won a and b candies respectively. Vladik offered 1 his candy to Valera. After that Valera gave Vladik 2 his candies, so that no one thought that he was less generous. Vladik for same reason gave 3 candies to Valera in next turn.

More formally, the guys take turns giving each other one candy more than they received in the previous turn.

This continued until the moment when one of them couldn’t give the right amount of candy. Candies, which guys got from each other, they don’t consider as their own. You need to know, who is the first who can’t give the right amount of candy.

Input

Single line of input data contains two space-separated integers ab (1 ≤ a, b ≤ 109) — number of Vladik and Valera candies respectively.

Output

Pring a single line "Vladik’’ in case, if Vladik first who can’t give right amount of candy, or "Valera’’ otherwise.

Example
Input
1 1
Output
Valera
Input
7 6
Output
Vladik


代码:

#include <iostream>
#include<cstdio>
#include<cstring>
#include<vector>
#include<queue>
using namespace std;

int n,m;
int main(){

cin>>n>>m;
int k=1;
while(1)
{
    if(n>=k)n=n-k;else {cout<<"Vladik"<<endl;break;}

    k++;
    if(m>=k)m=m-k;else {cout<<"Valera"<<endl;break;}

    k++;
}
    return 0;
}




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