Pandas 合并数据

最新推荐文章于 2024-05-29 16:21:04 发布

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最新推荐文章于 2024-05-29 16:21:04 发布

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分类专栏： Pandas

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http://blog.youkuaiyun.com/z1185196212/article/details/54613277

concat

先定义下资料集

import pandas as pd
import numpy as np
df1 = pd.DataFrame(np.ones((3,4))*0, columns=['a','b','c','d'])
df2 = pd.DataFrame(np.ones((3,4))*1, columns=['a','b','c','d'])
df3 = pd.DataFrame(np.ones((3,4))*2, columns=['a','b','c','d'])

printf df1
#     a    b    c    d
# 0  0.0  0.0  0.0  0.0
# 1  0.0  0.0  0.0  0.0
# 2  0.0  0.0  0.0  0.0

print df2
# 0  1.0  1.0  1.0  1.0
# 1  1.0  1.0  1.0  1.0
# 2  1.0  1.0  1.0  1.0

print df3
# 0  2.0  2.0  2.0  2.0
# 1  2.0  2.0  2.0  2.0
# 2  2.0  2.0  2.0  2.0
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axis

axis=0 代表上下的方向，axis=1 代表左右。

res = pd.concat([df1, df2, df3], axis=0)

#打印结果
print(res)
#     a    b    c    d
# 0  0.0  0.0  0.0  0.0
# 1  0.0  0.0  0.0  0.0
# 2  0.0  0.0  0.0  0.0
# 0  1.0  1.0  1.0  1.0
# 1  1.0  1.0  1.0  1.0
# 2  1.0  1.0  1.0  1.0
# 0  2.0  2.0  2.0  2.0
# 1  2.0  2.0  2.0  2.0
# 2  2.0  2.0  2.0  2.0
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ignore_index (重置 index)

#承上一个例子，并将index_ignore设定为True
res = pd.concat([df1, df2, df3], axis=0, ignore_index=True)

#打印结果
print(res)
#     a    b    c    d
# 0  0.0  0.0  0.0  0.0
# 1  0.0  0.0  0.0  0.0
# 2  0.0  0.0  0.0  0.0
# 3  1.0  1.0  1.0  1.0
# 4  1.0  1.0  1.0  1.0
# 5  1.0  1.0  1.0  1.0
# 6  2.0  2.0  2.0  2.0
# 7  2.0  2.0  2.0  2.0
# 8  2.0  2.0  2.0  2.0
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结果的index变0, 1, 2, 3, 4, 5, 6, 7, 8。

join (合并方式)

join=’outer’为预设值，因此未设定任何参数时，函数默认join=’outer’。此方式是依照column来做纵向合并，有相同的column上下合并在一起，其他独自的column个自成列，原本没有值的位置皆以NaN填充。

#纵向"外"合并df1与df2
res = pd.concat([df1, df2], axis=0, join='outer')

print(res)
#     a    b    c    d    e
# 1  0.0  0.0  0.0  0.0  NaN
# 2  0.0  0.0  0.0  0.0  NaN
# 3  0.0  0.0  0.0  0.0  NaN
# 2  NaN  1.0  1.0  1.0  1.0
# 3  NaN  1.0  1.0  1.0  1.0
# 4  NaN  1.0  1.0  1.0  1.0
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当join='inner' 时，

#纵向"内"合并df1与df2
res = pd.concat([df1, df2], axis=0, join='inner', ignore_index=True)
print(res)
#     b    c    d
# 0  0.0  0.0  0.0
# 1  0.0  0.0  0.0
# 2  0.0  0.0  0.0
# 3  1.0  1.0  1.0
# 4  1.0  1.0  1.0
# 5  1.0  1.0  1.0
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可以类比数据库中的内联接和外联接

join_axes (依照 axes 合并)

#依照`df1.index`进行横向合并
res = pd.concat([df1, df2], axis=1, join_axes=[df1.index])

#打印结果
print(res)
#     a    b    c    d    b    c    d    e
# 1  0.0  0.0  0.0  0.0  NaN  NaN  NaN  NaN
# 2  0.0  0.0  0.0  0.0  1.0  1.0  1.0  1.0
# 3  0.0  0.0  0.0  0.0  1.0  1.0  1.0  1.0

#移除join_axes，并打印结果
res = pd.concat([df1, df2], axis=1)
print(res)
#     a    b    c    d    b    c    d    e
# 1  0.0  0.0  0.0  0.0  NaN  NaN  NaN  NaN
# 2  0.0  0.0  0.0  0.0  1.0  1.0  1.0  1.0
# 3  0.0  0.0  0.0  0.0  1.0  1.0  1.0  1.0
# 4  NaN  NaN  NaN  NaN  1.0  1.0  1.0  1.0
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join_axes=[df1.index] 使横向合并时，以df1的索引为基准进行合并。

append (添加数据)

append只有纵向合并，没有横向合并。

#将df2合并到df1的下面，以及重置index，并打印出结果
res = df1.append(df2, ignore_index=True)
print(res)
#     a    b    c    d
# 0  0.0  0.0  0.0  0.0
# 1  0.0  0.0  0.0  0.0
# 2  0.0  0.0  0.0  0.0
# 3  1.0  1.0  1.0  1.0
# 4  1.0  1.0  1.0  1.0
# 5  1.0  1.0  1.0  1.0

#合并多个df，将df2与df3合并至df1的下面，以及重置index，并打印出结果
res = df1.append([df2, df3], ignore_index=True)
print(res)
#     a    b    c    d
# 0  0.0  0.0  0.0  0.0
# 1  0.0  0.0  0.0  0.0
# 2  0.0  0.0  0.0  0.0
# 3  1.0  1.0  1.0  1.0
# 4  1.0  1.0  1.0  1.0
# 5  1.0  1.0  1.0  1.0
# 6  1.0  1.0  1.0  1.0
# 7  1.0  1.0  1.0  1.0
# 8  1.0  1.0  1.0  1.0

#合并series，将s1合并至df1，以及重置index，并打印出结果
res = df1.append(s1, ignore_index=True)
print(res)
#     a    b    c    d
# 0  0.0  0.0  0.0  0.0
# 1  0.0  0.0  0.0  0.0
# 2  0.0  0.0  0.0  0.0
# 3  1.0  2.0  3.0  4.0
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merge

merge 很像数据库中的联接。

依据共同的一列进行合并

import pandas as pd
import numpy as np

#定义资料集并打印出
left = pd.DataFrame({'key': ['K0', 'K1', 'K2', 'K3'],
                             'A': ['A0', 'A1', 'A2', 'A3'],
                             'B': ['B0', 'B1', 'B2', 'B3']})
right = pd.DataFrame({'key': ['K0', 'K1', 'K2', 'K3'],
                              'C': ['C0', 'C1', 'C2', 'C3'],
                              'D': ['D0', 'D1', 'D2', 'D3']})

print left
#    A   B key
# 0  A0  B0  K0
# 1  A1  B1  K1
# 2  A2  B2  K2
# 3  A3  B3  K3

print right
#    C   D key
# 0  C0  D0  K0
# 1  C1  D1  K1
# 2  C2  D2  K2
# 3  C3  D3  K3

#依据key column合并，并打印出
res = pd.merge(left, right, on='key')

print(res)
     A   B key   C   D
# 0  A0  B0  K0  C0  D0
# 1  A1  B1  K1  C1  D1
# 2  A2  B2  K2  C2  D2
# 3  A3  B3  K3  C3  D3
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属性on 来表明依据某一行。

依据两组key合并

import pandas as pd

#定义资料集并打印出
left = pd.DataFrame({'key1': ['K0', 'K0', 'K1', 'K2'],
                      'key2': ['K0', 'K1', 'K0', 'K1'],
                      'A': ['A0', 'A1', 'A2', 'A3'],
                      'B': ['B0', 'B1', 'B2', 'B3']})
right = pd.DataFrame({'key1': ['K0', 'K1', 'K1', 'K2'],
                       'key2': ['K0', 'K0', 'K0', 'K0'],
                       'C': ['C0', 'C1', 'C2', 'C3'],
                       'D': ['D0', 'D1', 'D2', 'D3']})

print(left)
#    A   B key1 key2
# 0  A0  B0   K0   K0
# 1  A1  B1   K0   K1
# 2  A2  B2   K1   K0
# 3  A3  B3   K2   K1

print(right)
#    C   D key1 key2
# 0  C0  D0   K0   K0
# 1  C1  D1   K1   K0
# 2  C2  D2   K1   K0
# 3  C3  D3   K2   K0

#依据key1与key2 columns进行合并，并打印出四种结果['left', 'right', 'outer', 'inner']
res = pd.merge(left, right, on=['key1', 'key2'], how='inner')
print(res)
#    A   B key1 key2   C   D
# 0  A0  B0   K0   K0  C0  D0
# 1  A2  B2   K1   K0  C1  D1
# 2  A2  B2   K1   K0  C2  D2

res = pd.merge(left, right, on=['key1', 'key2'], how='outer')
print(res)
#     A    B key1 key2    C    D
# 0   A0   B0   K0   K0   C0   D0
# 1   A1   B1   K0   K1  NaN  NaN
# 2   A2   B2   K1   K0   C1   D1
# 3   A2   B2   K1   K0   C2   D2
# 4   A3   B3   K2   K1  NaN  NaN
# 5  NaN  NaN   K2   K0   C3   D3

res = pd.merge(left, right, on=['key1', 'key2'], how='left')
print(res)
#    A   B key1 key2    C    D
# 0  A0  B0   K0   K0   C0   D0
# 1  A1  B1   K0   K1  NaN  NaN
# 2  A2  B2   K1   K0   C1   D1
# 3  A2  B2   K1   K0   C2   D2
# 4  A3  B3   K2   K1  NaN  NaN

res = pd.merge(left, right, on=['key1', 'key2'], how='right')
print(res)
#     A    B key1 key2   C   D
# 0   A0   B0   K0   K0  C0  D0
# 1   A2   B2   K1   K0  C1  D1
# 2   A2   B2   K1   K0  C2  D2
# 3  NaN  NaN   K2   K0  C3  D3

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how属性有四种值，默认方式是inner 。当使用outter时空值用NaN填充。how='left'表示左外联接，how='right' 同理。

Indicator

indicator=True会将合并的方式作为新的一列。

import pandas as pd

#定义资料集并打印出
df1 = pd.DataFrame({'col1':[0,1], 'col_left':['a','b']})
df2 = pd.DataFrame({'col1':[1,2,2],'col_right':[2,2,2]})

print(df1)
#   col1 col_left
# 0     0        a
# 1     1        b

print(df2)
#   col1  col_right
# 0     1          2
# 1     2          2
# 2     2          2

# 依据col1进行合并，并启用indicator=True，最后打印出
res = pd.merge(df1, df2, on='col1', how='outer', indicator=True)
print(res)
#   col1 col_left  col_right      _merge
# 0   0.0        a        NaN   left_only
# 1   1.0        b        2.0        both
# 2   2.0      NaN        2.0  right_only
# 3   2.0      NaN        2.0  right_only

# 自定indicator column的名称，并打印出
res = pd.merge(df1, df2, on='col1', how='outer', indicator='indicator_column')
print(res)
#   col1 col_left  col_right indicator_column
# 0   0.0        a        NaN        left_only
# 1   1.0        b        2.0             both
# 2   2.0      NaN        2.0       right_only
# 3   2.0      NaN        2.0       right_only
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left_only表示只有左边的列表有值，right_only同理。

依据index合并

import pandas as pd

#定义资料集并打印出
left = pd.DataFrame({'A': ['A0', 'A1', 'A2'],
                     'B': ['B0', 'B1', 'B2']},
                     index=['K0', 'K1', 'K2'])
right = pd.DataFrame({'C': ['C0', 'C2', 'C3'],
                      'D': ['D0', 'D2', 'D3']},
                     index=['K0', 'K2', 'K3'])

print(left)
#     A   B
# K0  A0  B0
# K1  A1  B1
# K2  A2  B2

print(right)
#     C   D
# K0  C0  D0
# K2  C2  D2
# K3  C3  D3

#依据左右资料集的index进行合并，how='outer',并打印出
res = pd.merge(left, right, left_index=True, right_index=True, how='outer')
print(res)
#      A    B    C    D
# K0   A0   B0   C0   D0
# K1   A1   B1  NaN  NaN
# K2   A2   B2   C2   D2
# K3  NaN  NaN   C3   D3

#依据左右资料集的index进行合并，how='inner',并打印出
res = pd.merge(left, right, left_index=True, right_index=True, how='inner')
print(res)
#     A   B   C   D
# K0  A0  B0  C0  D0
# K2  A2  B2  C2  D2
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解决overlapping的问题

import pandas as pd

#定义资料集
boys = pd.DataFrame({'k': ['K0', 'K1', 'K2'], 'age': [1, 2, 3]})
girls = pd.DataFrame({'k': ['K0', 'K0', 'K3'], 'age': [4, 5, 6]})

#使用suffixes解决overlapping的问题
res = pd.merge(boys, girls, on='k', suffixes=['_boy', '_girl'], how='inner')
print(res)
#    age_boy   k  age_girl
# 0        1  K0         4
# 1        1  K0         5

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