罗马数字转换

原创于 2022-01-20 20:20:07 发布 · 303 阅读

0 ·

CC 4.0 BY-SA版权

文章标签：

#python

Python123题目参考答案__总结专栏收录该内容

135 篇文章

订阅专栏

str_get = input()

# ls1 = ['IV','IX','XL','XC','CD','CM']
# ls2 = [4, 9, 40, 90, 400, 900]
dt1 = {'I': 1, 'V': 5, 'X': 10, 'L': 50, 'C': 100, 'D': 500, 'M': 1000, 
       'IV': 4, 'IX': 9, 'XL': 40, 'XC': 90, 'CD': 400, 'CM': 900}
dt2 = {'IV': 4, 'IX': 9, 'XL': 40, 'XC': 90, 'CD': 400, 'CM': 900}
dt3 = {'I': 1, 'V': 5, 'X': 10, 'L': 50, 'C': 100, 'D': 500, 'M': 1000}

result = 0
for key in dt2.keys():
    if key in str_get:
        result+=dt1[key]*str_get.count(key)
        str_get = str_get.replace(key, '')
for key in dt3.keys():
    if key in str_get:
        result+=dt1[key]*str_get.count(key)
        str_get = str_get.replace(key, '')
print(result)