PAT_Basic --- 1002

PAT_Basic — 1002

**

1002. 写出这个数 (20)

**

读入一个自然数n，计算其各位数字之和，用汉语拼音写出和的每一位数字。

输入格式：每个测试输入包含1个测试用例，即给出自然数n的值。这里保证n小于10100。

输出格式：在一行内输出n的各位数字之和的每一位，拼音数字间有1 空格，但一行中最后一个拼音数字后没有空格。

输入样例：
1234567890987654321123456789
输出样例：
yi san wu

#include <iostream>
#include <string>

using namespace std;

void main(){
    char num[101] = {};
    char **name;
    name = (char**)malloc(sizeof(char*)* 10);
    name[0] = (char*)malloc(sizeof(char)* 10 * 5);
    for (int i = 0; i < 10; i++){
        name[i] = name[i - 1] + 5;
    }

    name[0] = "ling";
    name[1] = "yi";
    name[2] = "er";
    name[3] = "san";
    name[4] = "si";
    name[5] = "wu";
    name[6] = "liu";
    name[7] = "qi";
    name[8] = "ba";
    name[9] = "jiu";

    cin >> num;

    //char zero = '0';
    //int a = *num[1] - zero;
    //cout << a;
    int count = 0;
    for (int i = 0; i < 101; i++){
        if (num[i] == '\0')
            break;
        count += (num[i]) - '0';
    }
    cout << count << endl;

    char num_str[4] = {};
    sprintf(num_str, "%d", count);
    for (int i = 0; i < 4; i++){
        if (num_str[i] == '\0')
            break;

        int tmp = num_str[i] - '0';
        cout << name[tmp] << " ";
    }
    cout << endl;
    system("pause");
}