条件查询问题

$where  = array("usname"=>array('neq','1'));  //不等于

$map['status']   = array(in,"0,3"); //或者

//电话和用户名  都可以登陆的情况

$where['name']    =   I('post.username');

$where['mobile']   =  I('post.username');

$where['_logic']     = 'or';  //或者

$where['_complex'] = $map;  //合并
$where['password'] = md5(I('post.password'));

$where['title']      = array('LIKE', '%'.$title.'%');  //模糊查询

$where['time'] = array('between' ，array($start_time,$end_time)); //在此之间

$where['time'] = array('gt'，'$start_time');  //大于。。。

$where['time'] = array( 'lt'，'$end_time');   //小于。。。

ThinkPHP运算符 与 SQL运算符 对照表

TP运算符	SQL运算符	例子	实际查询条件
eq	=	$map['id'] = array('eq',100);	等效于：$map['id'] = 100;
neq	!=	$map['id'] = array('neq',100);	id != 100
gt	>	$map['id'] = array('gt',100);	id > 100
egt	>=	$map['id'] = array('egt',100);	id >= 100
lt	<	$map['id'] = array('lt',100);	id < 100
elt	<=	$map['id'] = array('elt',100);	id <= 100
like	like	$map<'username'> = array('like','Admin%');	username like 'Admin%'
between	between and	$map['id'] = array('between','1,8');	id BETWEEN 1 AND 8
not between	not between and	$map['id'] = array('not between','1,8');	id NOT BETWEEN 1 AND 8
in	in	$map['id'] = array('in','1,5,8');	id in(1,5,8)
not in	not in	$map['id'] = array('not in','1,5,8');	id not in(1,5,8)
and（默认）	and	$map['id'] = array(array('gt',1),array('lt',10));	(id > 1) AND (id < 10)
or	or	$map['id'] = array(array('gt',3),array('lt',10), 'or');	(id > 3) OR (id < 10)
xor（异或）	xor	两个输入中只有一个是true时，结果为true，否则为false，例子略。	1 xor 1 = 0
exp	综合表达式	$map['id'] = array('exp','in(1,3,8)');	$map['id'] = array('in','1,3,8');