Leetcode 392 Is Subsequence

Leetcode 392 Is Subsequence

Description

iven a string s and a string t, check if s is subsequence of t.
You may assume that there is only lower case English letters in both s and t. t is potentially a very long (length ~= 500,000) string, and s is a short string (<=100).
A subsequence of a string is a new string which is formed from the original string by deleting some (can be none) of the characters without disturbing the relative positions of the remaining characters. (ie, “ace” is a subsequence of “abcde” while “aec” is not).

Example 1:
s = "abc", t = "ahbgdc"
Return true. 
Example 2:
s = "axc", t = "ahbgdc"
Return false. 

题解

这道题比较简单,找出字符串s是否是t的字串,用bool数组ans从头到尾遍历,ans[i]为true的条件是s[i] == t[i]情况下i == 0或者ans[i - 1] == true,最后输出最后一位的值,代码如下:

class Solution {
public:
    bool isSubsequence(string s, string t) {
        if (s.size() <= 0)
            return true;
        vector<bool> ans(s.size(), false);
        int j = 0;
        for (int i = 0; i < t.size(); i++) {
            if (s[j] == t[i] && (s[j] || j == 0)) {
                ans[j++] = true;
            }
        }
        return ans[s.size() - 1];
    }
};
评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值