《算法笔记》codeup_100000578_B

最新推荐文章于 2022-05-23 20:22:38 发布

Zen_Ivan

最新推荐文章于 2022-05-23 20:22:38 发布

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本文链接：https://blog.youkuaiyun.com/Zen_Ivan/article/details/105793979

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本文介绍了一个C++程序，该程序能够将日期从“日月年”格式转换为具体的星期几。通过使用基姆拉尔森计算公式，程序能够准确地计算出输入日期是一周中的哪一天。此外，还提供了月份和星期名称的数组，以便于进行转换。

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解答：

#include <cstdio>
#include <iostream>
#include <cstring>
using namespace std;

/*
21 December 2012
5 January 2013
*/

char month_name[12][10] = {
"January", "February", "March", "April", "May", "June",
"July", "August", "September", "October", "November", "December",
};
char Week[7][10] = {
"Monday","Tuesday","Wednesday",
"Thursday","Friday","Saturday","Sunday"
};

int main() {
	 
	int year, month, day, week_of_day;
	char month_str[10];
	
	while(scanf("%d %s %d", &day, month_str, &year) != EOF) {
		//将月份字符串转换为数字 
		for(int i=0; i<12; i++) {
			if(!strcmp(month_str, month_name[i])) {
				month = i + 1;
				break;
			}
		}
		
		//使用基姆拉尔森计算公式计算出周几 
		if(month==1||month==2){
			month+=12;
			--year;
		}
		week_of_day = (day+2*month+3*(month+1)/5+year+year/4-year/100+year/400)%7;
		printf("%s\n", Week[week_of_day]);
	}
	
	return 0;
}