Dollars（简单DP）

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这是一个关于新西兰货币组成的问题，要求编写程序计算给定金额以不同方式组合的总数。输入包括一系列不超过$300.00的金额，每个金额都是5c的倍数。输出为每种金额及其可组合方式的数量。

J - Dollars

Time Limit:3000MS Memory Limit:0KB 64bit IO Format:%lld & %llu

Submit Status

Description

Dollars

New Zealand currency consists of $100, $50, $20, $10, and $5 notes and $2, $1, 50c, 20c, 10c and 5c coins. Write a program that will determine, for any given amount, in how many ways that amount may be made up. Changing the order of listing does not increase the count. Thus 20c may be made up in 4 ways: 1 20c, 2 10c, 10c+2 5c, and 4 5c.

Input

Input will consist of a series of real numbers no greater than $300.00 each on a separate line. Each amount will be valid, that is will be a multiple of 5c. The file will be terminated by a line containing zero (0.00).

Output

Output will consist of a line for each of the amounts in the input, each line consisting of the amount of money (with two decimal places and right justified in a field of width 6), followed by the number of ways in which that amount may be made up, right justified in a field of width 17.

Sample input

0.20
2.00
0.00

Sample output

  0.20                4
  2.00              293


简单DP，注意double强制转换会缺失精度，注意到数据的输入有特性，用整数读入；

AC代码：
      #include <iostream>
#include <cstdio>

using namespace std;

long long dp[33000];
int a[15] = {5,10,20,50,100,200,500,1000,2000,5000,10000};

int main()
{
//    freopen("in.txt","r",stdin);
//    double s,n;
    dp[0] = 1;
    for(int i = 0; i < 11; i++)
        for(int j = 5; j <= 30000; j += 5)
            if(j >= a[i])
                dp[j] += dp[j - a[i]];
    int a,b;
    while(~scanf("%d.%d",&a,&b)) //不能用double读入
    {
        long long x=a*100+b;
        if(x==0)break;
        printf("%6.2lf%17lld\n",(double) x / 100.0,dp[x]);
    }
    return 0;
}