459. Repeated Substring Pattern | 字符串重复子串序列

最新推荐文章于 2024-01-04 16:39:48 发布

Yangtong157

最新推荐文章于 2024-01-04 16:39:48 发布

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分类专栏： LeetCode

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本文介绍了一种通过检查字符串是否由其子串重复拼接而成的方法。利用遍历子串并多次连接来验证原始字符串，提供了具体的Java实现示例。

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Given a non-empty string check if it can be constructed by taking a substring of it and appending multiple copies of the substring together. You may assume the given string consists of lowercase English letters only and its length will not exceed 10000.

Example 1:

Input: "abab"

Output: True

Explanation: It's the substring "ab" twice.

Example 2:

Input: "aba"

Output: False

Example 3:

Input: "abcabcabcabc"

Output: True

Explanation: It's the substring "abc" four times. (And the substring "abcabc" twice.)

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思路，这道题应该用kmp算法的，奈何无法写出kmp算法，就用了一个时间更长的算法，即通过遍历子串，如果子串重复链接可以得到字符串的话就返回TRUE。

public class Solution {
   		public boolean repeatedSubstringPattern(String s) {
		int len = s.length();
		String sub = "";
		StringBuilder stringBuilder = new StringBuilder();
		for(int i= len/2;i>=1;i--){
			if (len%i==0) {
				int m = len/i;
				sub = s.substring(0, i);
				for(int k = 0;k<m;k++){
					stringBuilder.append(sub);
				}
				if (stringBuilder.toString().equals(s)) {
					return true;
				}
				stringBuilder.setLength(0);;
			}
		}
		return false;
	}
}