def test2():
a = [['一','一','二'],['一','二','三']]
for docno, document in enumerate(a):
print docno,','.join(document)
counter = defaultdict(int)
for w in sum(a,[]):
counter[w if isinstance(w, unicode) else unicode(w, 'utf-8')] += 1
print counter
print iteritems(counter)
print sum(itervalues(counter))
result = sorted(iteritems(counter), key=lambda d:d[1], reverse = True)
print result
python对字典降序排序
最新推荐文章于 2024-07-19 01:08:27 发布