数组遍历循环组成这种结构{513: [“＜“, 3], asd: [“≥“, 1]}和解构

原创已于 2022-02-22 16:19:31 修改 · 307 阅读

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于 2022-02-22 15:04:01 首次发布

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这段代码展示了如何基于`levelList`对象进行条件判断并构造新的对象`obj`，然后进行反向操作，将`obj`转换回`levelList`格式。主要涉及JavaScript对象的遍历、条件赋值及数组操作。

 let maxDa = "≥"
        let small = "<"
        let obj = {};
        for (var key in this.levelList) {
          if (this.levelList[key].where == 1) {
            obj[this.levelList[key].name] = [maxDa, this.levelList[key].num]
          } else if (this.levelList[key].where == 2) {
            obj[this.levelList[key].name] = [small, this.levelList[key].num]
          }
        }
      console.log(obj)

反向操作

 console.log("cheilde", res)
          let oneList = Object.keys(res.data)
          let cheilde = Object.values(res.data)
          let nameList = []
          let maxDa = "≥"
          let small = "<"
          oneList.map(item => {
            let name = item
            nameList.push({
              name: name,
            })
          })
          cheilde.map(item => {
            let math = ""
            let sum = ""
            if (maxDa == item[0]) {
              math = item[0]
              sum = item[1]
              nameList.map(clos => {
                clos.where = (1).toString()
                clos.num = item[1]
              })
              // console.log(item[0], item[1])
            } else if (small == item[0]) {
              nameList.map(clos => {
                clos.where = (2).toString()
                clos.num = item[1]
              })
            }
          })
        this.levelList= nameList