Ural 1001. Reverse Root(没有输入结束的坑爹题)

最新推荐文章于 2023-03-14 12:47:14 发布

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最新推荐文章于 2023-03-14 12:47:14 发布

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分类专栏： URAL 文章标签： Ural 水题

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本文介绍了一道简单的编程题目，要求对输入的一系列非负整数从后向前依次计算其平方根，并输出至少四位小数的结果。输入整数范围为0到10^18，采用标准输入输出方式。

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1001. Reverse Root

Time limit: 2.0 second
Memory limit: 64 MB

The problem is so easy, that the authors were lazy to write a statement for it!

Input

The input stream contains a set of integer numbers A_i (0 ≤ A_i ≤ 10¹⁸). The numbers are separated by any number of spaces and line breaks. A size of the input stream does not exceed 256 KB.

Output

For each number A_i from the last one till the first one you should output its square root. Each square root should be printed in a separate line with at least four digits after decimal point.

Sample

input	output
1427 0 876652098643267843 5276538	2297.0716 936297014.1164 0.0000 37.7757

input

output

0   
876652098643267843 
5276538

2297.0716
936297014.1164
0.0000
37.7757

AC代码：

#include <stdio.h>
#include <math.h>
double a[300000],p;
int main()
{
	int i=0,n;
	while(scanf("%lf",&p)!=EOF)//没有输入结束的标志
		a[i++]=sqrt(p);
	for(n=i-1;n>=0;n--)
		printf("%.4lf\n",a[n]);
	return 0;
}