00016

力扣 242 哈希表初步

class Solution:
    def isAnagram(self, s: str, t: str) -> bool:
        record = [0] * 26
        for i in s:
            record[ord(i) - ord("a")] += 1
        for i in t:
            record[ord(i) - ord("a")] -= 1
        for i in range(26):
            if record[i] != 0:
                return False
        return True

class Solution {
public:
    bool isAnagram(string s, string t) {
        int record[26] = {0};
        for(int i = 0; i< s.size(); i++){
            record[s[i] - 'a'] += 1;
        }
        for(int i = 0; i< t.size(); i++){
            record[t[i] - 'a'] -= 1;
        }
        for(int i = 0; i<26; i++){
            if(record[i] != 0){
                return false;
            }
        }
        return true;
    }
};