Given a list of N student records with name, ID and grade. You are supposed to sort the records with respect to the grade in non-increasing order, and output those student records of which the grades are in a given interval.
Input Specification:
Each input file contains one test case. Each case is given in the following format:
N name[1] ID[1] grade[1] name[2] ID[2] grade[2] ... ... name[N] ID[N] grade[N] grade1 grade2
where name[i] and ID[i] are strings of no more than 10 characters with no space, grade[i] is an integer in [0, 100], grade1 and grade2 are the boundaries of the grade's interval. It is guaranteed that all the grades are distinct.
Output Specification:
For each test case you should output the student records of which the grades are in the given interval [grade1, grade2] and are in non-increasing order. Each student record occupies a line with the student's name and ID, separated by one space. If there is no student's grade in that interval, output "NONE" instead.
Sample Input 1:4 Tom CS000001 59 Joe Math990112 89 Mike CS991301 100 Mary EE990830 95 60 100Sample Output 1:
Mike CS991301 Mary EE990830 Joe Math990112Sample Input 2:
2 Jean AA980920 60 Ann CS01 80 90 95Sample Output 2:
NONE
#include<iostream>
#include<vector>
#include<string>
#include<algorithm>
using namespace std;
struct student{
string name;
string ID;
int grade;
};
bool cmp(const student& stu1,const student& stu2){
if(stu1.grade < stu2.grade){
return true;
}else{
return false;
}
}
int main(){
for(int n;cin>>n;){
vector<student>students;
for(int i = 0;i < n; i++){
student temp;
cin>>temp.name>>temp.ID>>temp.grade;
students.push_back(temp);
}
sort(students.begin(),students.end(),cmp);
int min,max;
cin>>min>>max;
int count = 0;
for(int i = students.size()-1;i > -1;i--){
if(students[i].grade >= min && students[i].grade <= max){
cout<<students[i].name<<" "<<students[i].ID<<endl;
count++;
}
}
if(!count){
cout<<"NONE"<<endl;
}
}
return 0;
}
此博客详细介绍了如何对包含学生姓名、ID 和成绩的数据进行排序,并筛选出指定分数范围内的学生记录。通过使用C++编程语言实现,确保了数据处理的效率与准确性。
433

被折叠的 条评论
为什么被折叠?



