shǎ崽 OrOrOrOrz
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 7356 Accepted Submission(s): 3505
Problem Description
Acmer in HDU-ACM team are ambitious, especially shǎ崽, he can spend time in Internet bar doing problems overnight. So many girls want to meet and Orz him. But Orz him is not that easy.You must solve this problem first.
The problem is :
Give you a sequence of distinct integers, choose numbers as following : first choose the biggest, then smallest, then second biggest, second smallest etc. Until all the numbers was chosen .
For example, give you 1 2 3 4 5, you should output 5 1 4 2 3
The problem is :
Give you a sequence of distinct integers, choose numbers as following : first choose the biggest, then smallest, then second biggest, second smallest etc. Until all the numbers was chosen .
For example, give you 1 2 3 4 5, you should output 5 1 4 2 3
Input
There are multiple test cases, each case begins with one integer N(1 <= N <= 10000), following N distinct integers.
Output
Output a sequence of distinct integers described above.
Sample Input
5 1 2 3 4 5
Sample Output
5 1 4 2 3#include<stdio.h> #include<algorithm> using namespace std; int main() { int num[10050],i,right,left,n,flag; while(scanf("%d",&n)!=EOF) { flag=0; for(i=0;i<n;i++) { scanf("%d",&num[i]); } left=0;right=n-1; sort(num,num+n); while(left<=right) { if(left==right) { if(flag) printf(" "); printf("%d",num[left]); break; } if(flag) printf(" "); printf("%d",num[right--]); flag=1; if(flag) printf(" "); printf("%d",num[left++]); } printf("\n"); } return 0; }

本文介绍了一种通过输入序列,先选择最大数,然后选择最小数,以此类推,直到所有数字都被选择的算法。提供了一个C++实现示例,包括输入和输出说明。
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