A1134. Vertex Cover

最新推荐文章于 2021-10-31 10:21:01 发布

转载最新推荐文章于 2021-10-31 10:21:01 发布 · 183 阅读

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原文链接：http://www.cnblogs.com/zhuqiwei-blog/p/9553806.html

本文探讨了图论中的顶点覆盖问题，通过给定的图和顶点集，判断该集合是否为有效的顶点覆盖。介绍了如何利用哈希表进行高效验证，并附带示例代码。

A vertex cover of a graph is a set of vertices such that each edge of the graph is incident to at least one vertex of the set. Now given a graph with several vertex sets, you are supposed to tell if each of them is a vertex cover or not.

Input Specification:

Each input file contains one test case. For each case, the first line gives two positive integers

After the graph, a positive integer

where

Output Specification:

For each query, print in a line Yes if the set is a vertex cover, or No if not.

Sample Input:

10 11
8 7
6 8
4 5
8 4
8 1
1 2
1 4
9 8
9 1
1 0
2 4
5
4 0 3 8 4
6 6 1 7 5 4 9
3 1 8 4
2 2 8
7 9 8 7 6 5 4 2

Sample Output:

No
Yes
Yes
No
No

#include<iostream>
#include<cstdio>
using namespace std;
int N, M, edge1[20001], edge2[20001], pt = 0;
int hashV[20001] = {0};
int main(){
    scanf("%d%d",&N, &M);
    for(int i = 0; i < M; i++){
        scanf("%d%d", &edge1[i], &edge2[i]);
    }
    int K;
    scanf("%d", &K);
    for(int i = 0; i < K; i++){
        int Nv, tag = 1;
        scanf("%d", &Nv);
        fill(hashV, hashV + N, 0);
        for(int j = 0; j < Nv; j++){
            int vv;
            scanf("%d", &vv);
            hashV[vv] = 1;
        }
        for(int j = 0; j < M; j++){
            if(hashV[edge1[j]] == 0 && hashV[edge2[j]] == 0){
                tag = 0;
                break;
            }
        }
        if(tag == 0)
            printf("No\n");
        else printf("Yes\n");
    }
    cin >> N;
    return 0;
}

View Code

总结：

1、题意：给出一个图，然后给出一组点的集合，问这组点能否满足：图中任意一条边均包含至少一个集合中的点。

2、属于模拟题，不需要按照往常存储图的方法（邻接表、邻接矩阵）存储，只需要将每一条边存下来方便遍历即可。可按照edge1[N], edge2[N]的方式存储边。遍历时顺序遍历即可。查看点是否存在，可以将集合中的点都存在哈希表中。

转载于:https://www.cnblogs.com/zhuqiwei-blog/p/9553806.html