<?xml version="1.0" encoding="utf-8" ?><rss version="2.0"><channel><title><![CDATA[VioletCoor的博客]]></title><description><![CDATA[]]></description><link>https://blog.youkuaiyun.com/VioletCoor</link><language>zh-cn</language><generator>https://blog.youkuaiyun.com/</generator><copyright><![CDATA[Copyright &copy; VioletCoor]]></copyright><item><title><![CDATA[SQL生成连续日期用法]]></title><link>https://blog.youkuaiyun.com/VioletCoor/article/details/128579891</link><guid>https://blog.youkuaiyun.com/VioletCoor/article/details/128579891</guid><author>VioletCoor</author><pubDate>Fri, 06 Jan 2023 15:37:15 +0800</pubDate><description><![CDATA[SQL/Hive sql/Spark sql生成连续日期用法]]></description><category></category></item><item><title><![CDATA[Hive函数大全]]></title><link>https://blog.youkuaiyun.com/VioletCoor/article/details/128461767</link><guid>https://blog.youkuaiyun.com/VioletCoor/article/details/128461767</guid><author>VioletCoor</author><pubDate>Tue, 27 Dec 2022 21:40:58 +0800</pubDate><description><![CDATA[Hive函数大全]]></description><category></category></item><item><title><![CDATA[python解数独]]></title><link>https://blog.youkuaiyun.com/VioletCoor/article/details/106770346</link><guid>https://blog.youkuaiyun.com/VioletCoor/article/details/106770346</guid><author>VioletCoor</author><pubDate>Mon, 15 Jun 2020 20:24:12 +0800</pubDate><description><![CDATA[直接写出了解数独，中间过程超级复杂，主要思路也是平时解数独的思路：

遍历数组，找出每个空白处可以填写的数字
若存在有空白处可填写的数字只有1个，则直接填写，再次重复步骤1
若同行、同列、同一个九宫格这个数字只能填写在这里，填写后重复步骤1
若2、3都不行，则开始试数

2模块的代码：
# 判断每个空白处（为0的位置）可以填写的数字，若存在有空白处可填写的数字只有1个，则直接填写
for i in range(len(a)):
	black_num.append([]) # black_num为可填写的数字]]></description><category></category></item><item><title><![CDATA[在python列表中遇到的问题：列表b=列表a，修改列表b后a也会变]]></title><link>https://blog.youkuaiyun.com/VioletCoor/article/details/106116872</link><guid>https://blog.youkuaiyun.com/VioletCoor/article/details/106116872</guid><author>VioletCoor</author><pubDate>Thu, 14 May 2020 11:55:16 +0800</pubDate><description><![CDATA[对于列表构成的列表A：
列表B和C同时继承列表A中的某个列表，当对B进行扩展append()或者移除remove()操作时，C同时也会变化。
# 列表A
a=[[1, 2, 3], [1, 2, 3, 4], [2, 3, 4]]

# 列表B和C
b=a[1] # b=[1,2,3,4]
c=a[1] # c=[1,2,3,4]

# 扩展列表C
c.append(4) #c=[1,2,3,4,4]
# 此时列表A和列表B都有扩展
# a=[[1, 2, 3], [1, 2, 3, 4, 4], [2, ]]></description><category></category></item></channel></rss>