Struts2 chap02-02基本原理总结

最新推荐文章于 2019-08-29 09:08:00 发布

原创最新推荐文章于 2019-08-29 09:08:00 发布 · 485 阅读

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本文介绍了一个使用Struts2框架实现的简单登录系统案例，包括登录页面的设计、配置文件的设置、业务逻辑处理及视图展示等内容。

<%@ page language="java" contentType="text/html; charset=utf-8"
    pageEncoding="utf-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>Insert title here</title>
</head>
<body>
<form action="user" method="post">
<center>用户名：<input type="text" name="userName"/>
	密码：<input type="text" name="password"/>
<input type="submit" value="登录"/>
</form>
</center>	
</body>
</html>

struts.xml

<?xml version="1.0" encoding="UTF-8" ?>
<!DOCTYPE struts PUBLIC
    "-//Apache Software Foundation//DTD Struts Configuration 2.0//EN"
    "http://struts.apache.org/dtds/struts-2.0.dtd">

<struts>
	
  <package name="helloWorld" extends="struts-default">
  	<action name="hello" class="com.java.action.HelloWorldAction2">
  		<result name="success">helloWorld.jsp</result>
  	</action>
  <action name="user" class="com.java.action.UserAction">
  		<result name="success">success.jsp</result>
  		<result name="error">error.jsp</result>
  	</action>	
  </package>
</struts>

UserAction.java

package com.java.action;
import com.java.model.User;
import com.java.service.UserService;
import com.opensymphony.xwork2.ActionSupport;

public class UserAction extends ActionSupport{

	private static final long serialVersionUID = 1L;	
	
	private UserService userService=new UserService();
	private String userName;
	private String password;
	
	public String getUserName() {
		return userName;
	}

	public void setUserName(String userName) {
		this.userName = userName;
	}

	public String getPassword() {
		return password;
	}

	public void setPassword(String password) {
		this.password = password;
	}
	private String name;
	public String getName() {
		return name;
	}
	public void setName(String name) {
		this.name = name;
	}
	@Override
	public String execute() throws Exception {
		System.out.println("执行了UserAction的默认方法");
		User user=new User();
		user.setUsername(userName);
		user.setPassword(password);
		if(userService.login(user)){
			return SUCCESS;
		}else{
			return ERROR;
		}
	}
}

User.java

package com.java.model;

public class User {
	private String username;
	private String password;
	public String getUsername() {
		return username;
	}
	public void setUsername(String username) {
		this.username = username;
	}
	public String getPassword() {
		return password;
	}
	public void setPassword(String password) {
		this.password = password;
	}
}

UserService.java

package com.java.service;

import com.java.model.User;

public class UserService {

	public boolean login(User user){
		if("java".equals(user.getUsername())&&"20160827".equals(user.getPassword())){
			return true;
		}else{
			return false;
		}
	}
}

success.jsp

<%@ page language="java" contentType="text/html; charset=utf-8"
    pageEncoding="utf-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>Insert title here</title>
</head>
<body>
登录成功！
</body>
</html>

error.jsp

<%@ page language="java" contentType="text/html; charset=utf-8"
    pageEncoding="utf-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>Insert title here</title>
</head>
<body>
登录失败！
</body>
</html>