LeetCode 292 -Nim Game ( JAVA )

本文介绍了一种Nim游戏的胜负判断策略。在一个由你和朋友轮流从一堆石头中移除1到3颗石头的游戏里,如何确保自己赢得比赛?通过分析游戏规则,本文提供了一个简洁的解决方案来确定在给定初始石头数量的情况下是否能够获胜。

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You are playing the following Nim Game with your friend: There is a heap of stones on the table, each time one of you take turns to remove 1 to 3 stones. The one who removes the last stone will be the winner. You will take the first turn to remove the stones.

Both of you are very clever and have optimal strategies for the game. Write a function to determine whether you can win the game given the number of stones in the heap.

For example, if there are 4 stones in the heap, then you will never win the game: no matter 1, 2, or 3 stones you remove, the last stone will always be removed by your friend.

Hint:

  1. If there are 5 stones in the heap, could you figure out a way to remove the stones such that you will always be the winner?

public class Solution {
    public boolean canWinNim(int n) {
        return n % 4 != 0;
    }
}




总结:注意for example 如果是4肯定就输,由此可向后推,只要数是4的备注,就肯定输

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