Difficulty : easy
Given an array of integers, return indices of the two numbers such that they add up to a specific target.
You may assume that each input would have exactly one solution.
Example:
Given nums = [2, 7, 11, 15], target = 9, Because nums[0] + nums[1] = 2 + 7 = 9, return [0, 1].
public class Solution {
public int[] twoSum(int[] nums, int target) {
int [] a = new int[2];
for(int i=0;i<nums.length;i++){
for(int j=0;j<nums.length;j++){
if(i!=j&&target==nums[i]+nums[j]){
a[0]=i;
a[1]=j;
break;
}
}
}
return a;
}
}
总结:题目比较简单,使用两个循环嵌套即可,空间复杂度O(N2),代码效率不高。