https://blog.youkuaiyun.com/Ttencezh-cnhttps://blog.youkuaiyun.com/https://blog.youkuaiyun.com/Ttence/article/details/149750257https://blog.youkuaiyun.com/Ttence/article/details/149750257TtenceWed, 30 Jul 2025 09:11:36 +0800https://blog.youkuaiyun.com/Ttence/article/details/149749355https://blog.youkuaiyun.com/Ttence/article/details/149749355TtenceTue, 29 Jul 2025 16:12:04 +0800https://blog.youkuaiyun.com/Ttence/article/details/145520901https://blog.youkuaiyun.com/Ttence/article/details/145520901TtenceSun, 09 Feb 2025 16:06:03 +0800https://blog.youkuaiyun.com/Ttence/article/details/145511654https://blog.youkuaiyun.com/Ttence/article/details/145511654TtenceSat, 08 Feb 2025 18:00:41 +0800& nums1是第一个数组的引用，int m是有效元素数量；注意，因为 m = 0 ，所以 nums1 中没有元素。nums1 中仅存的 0 仅仅是为了确保合并结果可以顺利存放到 nums1 中。通过两个指针来遍历nums1和nums2，并合并在cur中，最后用sorted替换储存。,5,6] ，其中斜体加粗标注的为 nums1 中的元素。需要合并 [1,2,3] 和 [2,5,6]。需要合并的数组是 [] 和 [1]。中，使合并后的数组同样按。]]>https://blog.youkuaiyun.com/Ttence/article/details/144471999https://blog.youkuaiyun.com/Ttence/article/details/144471999TtenceSat, 14 Dec 2024 15:59:45 +0800= 0;i--) {j >= 0;j--) {= '*') {continue;]]>https://blog.youkuaiyun.com/Ttence/article/details/144471882https://blog.youkuaiyun.com/Ttence/article/details/144471882TtenceSat, 14 Dec 2024 15:55:12 +0800https://blog.youkuaiyun.com/Ttence/article/details/144471817https://blog.youkuaiyun.com/Ttence/article/details/144471817TtenceSat, 14 Dec 2024 15:49:52 +0800 i + j = (m + n + 1) / 2。// m + n为奇数：i + j = (m - i) + (n - j) + 1 定义左边比右边多一个。// m + n为偶数：i + j = (m - i) + (n - j)// 对i进行二分查找 j可以通过i计算出来。// 规定i在分割线右边 所以i可以取m。]]>