C++扫雷代码

#include <ctime>
#include <cstdlib>
#include <iostream>
using namespace std;

int map[12][12];    // 为避免边界的特殊处理，故将二维数组四周边界扩展1
int derection[3] = { 0, 1, -1 };  //方向数组

int calculate ( int x, int y )
{
	int counter = 0;
	for ( int i = 0; i < 3; i++ )
		for ( int j = 0; j < 3; j++ )
			if ( map[ x+derection[i]][ y+derection[j] ] == 9 )
				counter++;                 // 统计以(x,y)为中心的四周的雷数目
			return counter;
}

void game ( int x, int y )
{
    if ( calculate ( x, y ) == 0 )
	{
		map[x][y] = 0;
		for ( int i = 0; i < 3; i++ )
		{                                  // 模拟游戏过程，若点到一个空白，则系统自动向外扩展
			for ( int j = 0; j < 3; j++ )
				if ( x+derection[i] <= 9 && y+derection[j] <= 9 && x+derection[i] >= 1 && y+derection[j] >= 1
					&& !( derection[i] == 0 && derection[j] == 0 ) &&  map[x+derection[i]][y+derection[j]] == -1 ) 
					game( x+derection[i], y+derection[j] ); // 条件比较多，一是不可以让两个方向坐标同时为0，否则
				递归调用本身！
		}                                                      //二是递归不能出界.三是要保证不返回调用。
	}
	else
		map[x][y] = calculate(x,y);
}


void print ()
{
	for ( int i = 1; i < 10; i++ )
	{
		for ( int j = 1; j < 10; j++ )
		{
			if ( map[i][j] == -1 || map[i][j] == 9 )
				cout << "#";
			else
				cout << map[i][j];
		}
		cout << endl;
	}
}


bool check ()
{
	int counter = 0;
	for ( int i = 1; i < 10; i++ )
		for ( int j = 1; j < 10; j++ )
			if ( map[i][j] != -1 )
				counter++;
			if ( counter == 10 )
				return true;
			else
				return false;
}


int main ()
{
	
	int i, j, x, y;
	char ch; 
	srand ( time ( 0 ) );
	
	do
	{
		memset ( map, -1, sizeof(map) );  // 将map全部初始化为-1，以后用-1表示未涉及的区域
		
		for ( i = 0; i < 10;  )
		{
			x = rand()%9 + 1;
			y = rand()%9 + 1;
			if ( map[x][y] != 9 )
			{
				map[x][y] = 9;
				i++;
			}
		}
		
		for ( i = 1; i < 10; i++ )
		{
			for ( j = 1; j < 10; j++ )
				cout << "#";
			cout << "\n";
		}
		cout << "\n";
		
		cout << "Please enter a coordinate: ";
		while ( cin >> x >> y )
		{
			if ( map[x][y] == 9 )
			{
				cout << "GAME OVER" << endl;    //点中雷之后游戏结束，并且输出雷的位置
				for ( i = 1; i < 10; i++ )
				{
					for ( j = 1; j < 10; j++ )
					{
						if ( map[i][j] == 9 )
							cout << "@";
						else
							cout << "#";
					}
					cout << endl;
				}
				break;
			}
			
			game(x,y);
			print();
			
			if ( check () )
			{
				cout << "YOU WIN" << endl;
				break;
			}
			cout << "\n\n";
		}
		
		cout << "Do you want to play again, if true enter Y, or enter N" << endl;
		cin >> ch;
		cout << "\n\n";
	} while ( ch == 'Y' );
	
	return 0;
}