数据的累加

题目描述

calculate sum(n) = 1 + 2 + 3 + ... + n。

输入

The input will consist of a series of integers n, one integer per line.

输出

For each case, output SUM(n) in one line,  followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.

样例输入

1

10

样例输出

1

55

答案;

#include<stdio.h>
int main()
{
    int n;
    while(scanf("%d",&n)!=EOF)
    {
        int i;
        int sum=0;
        for(i=1;i<=n;i++)
        sum+=i;
        printf("%d\n\n",sum);
    }
    return 0;
}