T04 Grading

 

 

 

#include<iostream>
#include <iomanip>

#define abs(x) (x>0?(x):(-x))
using namespace std;

double is_in(int g1, int g2, int t) {      // 判断差是否在公差范围内
    if (abs(g1 - g2) <= t) {
        return (double) (g1 + g2) / 2;
    } else {
        return -1;
    }
}

double close(int g3, int g1, int g2) {     // 找到与g3最接近的那个数并求其平均值
    if (abs(g3 - g1) >= abs(g3 - g2)) {
        return (double) (g3 + g2) / 2;
    } else {
        return (double) (g3 + g1) / 2;
    }
}

int main(void) {
    int p, t, g1, g2, g3, gj;
    ::scanf("%d%d%d%d%d", &p, &t, &g1, &g2, &g3, &gj);
    
    if (is_in(g1, g2, t)) 
    {
        cout << fixed << setprecision(1) << is_in(g1, g2, t);
    }
    else if (is_in(g1, g3, t) && is_in(g2, g3, t)) 
    {
        cout << fixed << setprecision(1) << max(max(g1, g2), g3);
    } 
    else if (is_in(g1, g3, t) || is_in(g2, g3, t)) 
    {
        cout << fixed << setprecision(1) << close(g3, g1, g2);
    } 
    else 
    {
        cout << fixed << setprecision(1) << (double) gj;
    }
}

要注意要求的输出值是保留了小数点后一位，我用的cout输出，保留小数点后一位的话语法是

cout << fixed << setprecision(1) << (double) gj;

如果不用fixed，那么保留的就是有效数字1位，就不是从小数点后开始算起的了