Palindromes

Description
A regular palindrome is a string of numbers or letters that is the same forward as backward. For example, the string “ABCDEDCBA” is a palindrome because it is the same when the string is read from left to right as when the string is read from right to left.

A mirrored string is a string for which when each of the elements of the string is changed to its reverse (if it has a reverse) and the string is read backwards the result is the same as the original string. For example, the string “3AIAE” is a mirrored string because “A” and “I” are their own reverses, and “3” and “E” are each others’ reverses.

A mirrored palindrome is a string that meets the criteria of a regular palindrome and the criteria of a mirrored string. The string “ATOYOTA” is a mirrored palindrome because if the string is read backwards, the string is the same as the original and because if each of the characters is replaced by its reverse and the result is read backwards, the result is the same as the original string.

Of course,”A”,”T”, “O”, and “Y” are all their own reverses.

A list of all valid characters and their reverses is as follows.

Character Reverse Character Reverse Character Reverse
A A M M Y Y
B N Z 5
C O O 1 1
D P 2 S
E 3 Q 3 E
F R 4
G S 2 5 Z
H H T T 6
I I U U 7
J L V V 8 8
K W W 9
L J X X

Note that O (zero) and 0 (the letter) are considered the same character and therefore ONLY the letter “0” is a valid character.

Input
Input consists of strings (one per line) each of which will consist of one to twenty valid characters. There will be no invalid characters in any of the strings. Your program should read to the end of file.

Output
For each input string, you should print the string starting in column 1 immediately followed by exactly one of the following strings.

STRING CRITERIA
” – is not a palindrome.” if the string is not a palindrome and is not a mirrored string
” – is a regular palindrome.” if the string is a palindrome and is not a mirrored string
” – is a mirrored string.” if the string is not a palindrome and is a mirrored string
” – is a mirrored palindrome.” if the string is a palindrome and is a mirrored string
Note that the output line is to include the -’s and spacing exactly as shown in the table above and demonstrated in the Sample Output below.

In addition, after each output line, you must print an empty line.

Sample Input
NOTAPALINDROME
ISAPALINILAPASI
2A3MEAS
ATOYOTA
Sample Output
NOTAPALINDROME – is not a palindrome.

ISAPALINILAPASI – is a regular palindrome.

2A3MEAS – is a mirrored string.

ATOYOTA – is a mirrored palindrome.
Hint
use the C++’s class of string will be convenient, but not a must
问一串字符是什么样的字符，判断标准：1，是否是回文；2，是否是镜子体文字。
直接写两个函数判断一下就好了，别的没什么。

#include<cstdio>
#include<cstring>
#include<iostream>
#include<string>
#include<queue>
#include<algorithm>
using namespace std;
char a[100];
int check1(int len)
{
    int i, leap;
    for (i = 0; i < len; i++)
    {
        if (a[i] != a[len - i - 1])break;
    }
    if (i == len)return 1;
    else return 0;
}
int check2(int len)
{
    int i, leap;
    for (i = 0; i < len; i++)
    {
        if (a[i] == 'A'&&a[i] == a[len - 1 - i])continue;
        else if (a[i] == 'E'&&a[len - 1 - i] == '3')continue;
        else if (a[i] == 'H'&&a[len - i - 1] == 'H')continue;
        else if (a[i] == 'I'&&a[len - 1 - i] == 'I')continue;
        else if (a[i] == 'J'&&a[len - 1 - i] == 'L')continue;
        else if (a[i] == 'L'&&a[len - 1 - i] == 'J')continue;
        else if (a[i] == 'M'&&a[len - 1 - i] == 'M')continue;
        else if (a[i] == 'O'&&a[len - i - 1] == 'O')continue;
        else if (a[i] == 'S'&&a[len - i - 1] == '2')continue;
        else if (a[i] == 'T'&&a[len - i - 1] == 'T')continue;
        else if (a[i] == 'U'&&a[len - i - 1] == 'U')continue;
        else if (a[i] == 'V'&&a[len - i - 1] == 'V')continue;
        else if (a[i] == 'W'&&a[len - i - 1] == 'W')continue;
        else if (a[i] == 'X'&&a[len - i - 1] == 'X')continue;
        else if (a[i] == 'Y'&&a[len - i - 1] == 'Y')continue;
        else if (a[i] == 'Z'&&a[len - i - 1] == '5')continue;
        else if (a[i] == '1'&&a[len - i - 1] == '1')continue;
        else if (a[i] == '2'&&a[len - i - 1] == 'S')continue;
        else if (a[i] == '3'&&a[len - i - 1] == 'E')continue;
        else if (a[i] == '5'&&a[len - i - 1] == 'Z')continue;
        else if (a[i] == '8'&&a[len - i - 1] == '8')continue;
        else break;
    }
    if (i == len)return 1;
    else return 0;
}
int main()
{
    int i, j, m, n, ans, len, leap1, leap2;
    while (gets(a))
    {
        len = strlen(a);
        leap1 = check1(len);
        leap2 = check2(len);
        cout << a;
        if (leap1&&leap2)
            cout << " -- is a mirrored palindrome." << endl << endl;
        else if (leap1&&!leap2)
            cout << " -- is a regular palindrome." << endl << endl;
        else if (!leap1&&leap2)
            cout << " -- is a mirrored string." << endl << endl;
        else if (!leap1&&!leap2)
            cout << " -- is not a palindrome." << endl << endl;
    }
    return 0;
}