题目描述
请实现一个函数,将一个字符串中的每个空格替换成“%20”。例如,当字符串为We Are Happy.则经过替换之后的字符串为We%20Are%20Happy。
class Solution {
public:
void replaceSpace(char *str,int length) {
//记录空格总数,length表示字符串的长度
int count = 0;
for(int i = 0; i < length; i++){
if(str[i] == ' ')
count++;
}
//从后往前替换
for(int i = length - 1; i >= 0; i--){
if(str[i] != ' ')
str[i + count * 2] = str[i];
else{
count--;
str[i + count * 2] = '%';
str[i + count * 2 + 1] = '2';
str[i + count * 2 + 2] = '0';
}
}
str[length + count * 2] = '\0';
}
};