博客介绍了如何运用扩展欧几里得算法解决POJ 2115题目——C Looooops（CTU Open 2004）。该问题要求找到最小解ax=b (mod n)，其中a=C, b=B-A, n=2k。通过算法实现，可以高效求解此类模线性方程。"
110863587,10296763,Excel中文本型数字与数值型数字的转换,"['Excel技巧', '数据处理', '文本格式', '数值格式']
Description
A Compiler Mystery: We are given a C-language style for loop of type
I.e., a loop which starts by setting variable to value A and while variable is not equal to B, repeats statement followed by increasing the variable by C. We want to know how many times does the statement get executed for particular values of A, B and C, assuming that all arithmetics is calculated in a k-bit unsigned integer type (with values 0 <= x < 2k) modulo 2k.
for (variable = A; variable != B; variable += C) statement;
I.e., a loop which starts by setting variable to value A and while variable is not equal to B, repeats statement followed by increasing the variable by C. We want to know how many times does the statement get executed for particular values of A, B and C, assuming that all arithmetics is calculated in a k-bit unsigned integer type (with values 0 <= x < 2k) modulo 2k.
Input
最低0.47元/天 解锁文章
扫一扫
483
被折叠的 条评论
为什么被折叠?
到【灌水乐园】发言
