Fizz Buzz ----LeetCode

最新推荐文章于 2022-05-04 23:51:32 发布

TLChao

最新推荐文章于 2022-05-04 23:51:32 发布

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分类专栏：练习算法文章标签： LeetCode FizzBuzz

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本文介绍了一个简单的程序，该程序能够输出从1到n的数字，其中3的倍数被Fizz代替，5的倍数被Buzz代替，同时为15的倍数的数字则被FizzBuzz代替。提供了C++实现代码示例。

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Write a program that outputs the string representation of numbers from 1 to n.

But for multiples of three it should output “Fizz” instead of the number and for the multiples of five output “Buzz”. For numbers which are multiples of both three and five output “FizzBuzz”.

Example:

n = 15,

Return:
[
    "1",
    "2",
    "Fizz",
    "4",
    "Buzz",
    "Fizz",
    "7",
    "8",
    "Fizz",
    "Buzz",
    "11",
    "Fizz",
    "13",
    "14",
    "FizzBuzz"
]

C++:

#include <iostream>
using namespace std;


int _tmain(int argc, _TCHAR* argv[])
{
	int n;
	cout<<"请输入n:";
	cin>>n;
	cout<<endl;
	for(int i=1;i<=n;i++)
	{
		if(i%15==0)
		{
			cout<<i<<":"<<"Fizz Buzz"<<endl;
		
		}
		else if(i%3==0)
		{
				cout<<i<<":"<<"Fizz"<<endl;
		}
		
		else if(i%5==0)
		{
				cout<<i<<":"<<"Buzz"<<endl;
		}
		else
		{
			cout<<i<<endl;
		}
		}
	system("PAUSE");
	 return 0;
}