【Linux】循环while&for

while
当n小于10时输出n的值

#!/bin/bash
n=1
while [ $n -lt 10 ]
do
        echo "$n"
        n=$[$n+1]
done

for

#!/bin/bash
for n in {1..9}
do
        echo "$n"
done

for语句其他形式:
for((n=1;n<10;n++))
for i in $(seq 1 9)
for i in one two three