LeetCode - 26: Remove Duplicates from Sorted Array

本文提供两种Python方法实现:在不使用额外空间的情况下,去除已排序数组中的重复元素,并返回处理后数组的新长度。第一种方法利用集合(set)特性进行去重并重新排序;第二种方法采用双指针技巧逐一遍历比较并更新数组。

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26、Remove Duplicates from Sorted Array

Given a sorted array nums, remove the duplicates in-place such that each element appear only once and return the new length.
Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.

Example:

Given nums = [1,1,2], Your function should return length = 2, with the
first two elements of nums being 1 and 2 respectively. It doesn’t
matter what you leave beyond the returned length.

Solution-1 - Python:

def removeDuplicates(self, nums):
    """
    :type nums: List[int]
    :rtype: int
    """
    nums[:] = list(set(nums))
    nums.sort()
    return len(nums)

Solution-2 - Python:

#!/usr/bin/env python
# -*- coding = utf-8 -*-

"""
 @ Create Time: 2018/4/28
 @ Author: songpo.zhang
 @ Target:
"""

def removeDuplicates(nums):
    n = 0
    for i in range(1, len(nums)):
        if nums[n] != nums[i]:
            n += 1
            nums[n] = nums[i]
    return n + 1

nums = [1,1,1,2]
print((removeDuplicates(nums)))

不知道具体什么原因,在leetcode上提交时,第二种解法总是报错……

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