922.按奇偶排序数组Ⅱ

class Solution {
    public int[] sortArrayByParityII(int[] nums) {
        int j = 1;// 下标
        for(int i = 0; i < nums.length - 1; i += 2){
            if((nums[i] % 2) != 0){
                while((nums[j] % 2) != 0) j += 2;
                int temp = nums[i];
                nums[i] = nums[j];
                nums[j] = temp;
            }
        }
        return nums;
    }
}